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In DeltaPQR,anglePQR=90^(@), as show in ...

In `DeltaPQR,anglePQR=90^(@),` as show in figure, seg `QSbotsidePR,` seg QM is angle bisector of `anglePQR.`
Prove that : `(PM^(2))/(MR^(2))=(PS)/(SR)`

Text Solution

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The correct Answer is:
`therefore(PM^(2))/(MR^(2))=(PS)/(SR)`
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In angle ACD=90^(@) and CD bot AB . Prove that (BC^(2))/(AC^(2))=(BD)/(AD)

In DeltaPQR seg RS is bisector of anglePRQ.PS=6, SQ=8,PR=15 . Find QR.

Knowledge Check

  • In Delta PQR, angle PQR = 90^(@), "seg" QM bot hyp PR, PM = 16 and RM = 9 then QM…….

    A
    12
    B
    25
    C
    7
    D
    `16 xx 9`

  • In DeltaPQR seg RS is the bisector of anglePQR,PS=8, SQ=6,PR=20" then " QR = …………….

    A
    10
    B
    15
    C
    30
    D
    40

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