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In DeltaPQR,anglePQR=90^(@), as show in ...

In `DeltaPQR,anglePQR=90^(@),` as show in figure, seg `QSbotsidePR,` seg QM is angle bisector of `anglePQR.`
Prove that : `(PM^(2))/(MR^(2))=(PS)/(SR)`

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The correct Answer is:
`therefore(PM^(2))/(MR^(2))=(PS)/(SR)`
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