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The dissociation constant of an acid is ...

The dissociation constant of an acid is `1xx10^(-5)`. The `pH` of its `0.1 M` solution will be approximately

A

`6`

B

`4`

C

`3`

D

`5`

Text Solution

Verified by Experts

The correct Answer is:
C
`[H_(3)O^(+)]=sqrt(K_(a)xxC)=sqrt(10^(-5)xx0.1)=10^(-3)`
`pH= -log10^(-3)=3`
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