The dissociation constant of an acid is ...

The dissociation constant of an acid is `1xx10^(-5)`. The `pH` of its `0.1 M` solution will be approximately

A

`6`

B

`4`

C

`3`

D

`5`

Text Solution

Verified by Experts

The correct Answer is:

C

`[H_(3)O^(+)]=sqrt(K_(a)xxC)=sqrt(10^(-5)xx0.1)=10^(-3)`
`pH= -log10^(-3)=3`

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Knowledge Check

The dissociation constant of an acid, HA is 1 x 10^-5 The pH of 0.1 M solution of the acid will be

A

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B

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C

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D

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The dissociation constant of an acid HA is 1 xx 10^(-5). The pH of 0.1 molar solution of the acid will be approximately

A

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B

5

C

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D

6

The dissociation constant of an acid HA is 1 xx 10^(-5) . The pH of 0.1 molar solution of the acid will be

A

Five

B

Four

C

Three

D

One

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