Home
Class 11
CHEMISTRY
If the degree of ionization of water be ...

If the degree of ionization of water be `1.8xx10^(-9)` at `298 K`. Its ionization constant will be

A

`1.8xx10^(-16)`

B

`1xx10^(-14)`

C

`1xx10^(-16)`

D

`1.67xx10^(-14)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(a)=(K_(W))/([H_(2)O])=(10^(-14))/(55.5)=1.8xx10^(-16)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • IONIC EQUILIBIUM

    A2Z|Exercise AIPMT/ NEET/ AIIMS Questions|80 Videos

  • HYDROGEN

    A2Z|Exercise Section D - Chapter End Test|30 Videos

  • MOCK TEST

    A2Z|Exercise Mock Test 2|45 Videos

Similar Questions

Explore conceptually related problems

The degree of dissociation of water is 1.8 xx10^(-9) at 298 K . Calculate the ionization constant and Ionic product of water at 298 K .

At 25^@C the degree of ionization of water was found to be 1.8 xx 10^(–9) . Calculate the ionization constant and ionic product of water at this temperature

Knowledge Check

  • If the degree of ionization of water be 1.8 xx 10^(-9) at 298K. Its ionization constant will be

    A
    `1.8 xx 10^(-16)`
    B
    `1 xx 10^(-14)`
    C
    `1 xx 10^(-16)`
    D
    `1.67 xx 10^(-14)`

  • If the degree of ionization of water is 1.8xx10^(-9) at 298K . Its ionization constant will be

    A
    `1.8xx10^(-16)`
    B
    `1xx10^(-14)`
    C
    `1xx10^(-16)`
    D
    `1.67xx10^(-14)`

  • The degree of ionization increases

    A
    with increase in concentration of the solution
    B
    on addition of excess of water to the solution
    C
    on decreasing the temperature of the solution
    D
    on stirring the solution vigorousoly.

    • Similar Questions

    Explore conceptually related problems

    Calculate the degree of ionization of pure water at 25^@C .

    What is the pH of 0.001 M aniline solution? The ionization constant of aniline 4.27xx10^(-10) . Calculate the degree of ionization of aniline in the solution. Also calculate the ionization constant of the conjustant acid of aniline.

    The ionization constant of aniline is 4.3xx10^(-10) (i)Calculate the pH of 0.001 M aniline solution , (ii)Calculate the degree of ionization of aniline in the solution. (iii)Calculate ionization constant of the conjugate acid of aniline.

    A 0.01 M solution of acetic acid is 1.34 % ionised (degree of dissociation = 0.0134) at 298 K. What is the ionization constant of acetic acid ?

    A 0.20 M solution of methanoic acid has degree of ionization of 0.032. Its dissociation constant would be

    Home
    Profile