For a dipole, the value of each charge is 10–10 stat coulomb and their separation is 1Å, then its dipole moment is :–

Options

A. one debye
B. 2 debye
C. `10^(–3)` debye
D. `3xx 10^(–20)` debye

Explanation

To find the dipole moment \( p \) of a dipole consisting of two equal and opposite charges, we can use the formula:

\[ p = q \cdot d \]

where:
- \( p \) is the dipole moment,
- \( q \) is the magnitude of one of the charges, and
- \( d \) is the separation between the charges.

### Step 1: Identify the values given in the problem.
- Each charge \( q = 10^{-10} \) stat coulomb.
- Separation \( d = 1 \) Å (which is \( 1 \times 10^{-10} \) m).

### Step 2: Convert the charge from stat coulombs to coulombs.
We know that:
1 stat coulomb = \( 3.33 \times 10^{-10} \) coulombs.

Thus, we can convert \( q \):
\[ q = 10^{-10} \text{ stat coulomb} \times 3.33 \times 10^{-10} \text{ coulomb/stat coulomb} = 3.33 \times 10^{-20} \text{ coulombs} \]

### Step 3: Calculate the dipole moment using the formula.
Now substituting the values into the dipole moment formula:
\[ p = q \cdot d = (3.33 \times 10^{-20} \text{ C}) \cdot (1 \times 10^{-10} \text{ m}) \]

Calculating this gives:
\[ p = 3.33 \times 10^{-30} \text{ C m} \]

### Step 4: Convert the dipole moment to Debye.
We know that:
1 Debye \( = 3.33 \times 10^{-30} \text{ C m} \).

Thus, we can express the dipole moment in Debye:
\[ p = \frac{3.33 \times 10^{-30} \text{ C m}}{3.33 \times 10^{-30} \text{ C m/Debye}} = 1 \text{ Debye} \]

### Final Answer:
The dipole moment \( p \) is \( 1 \) Debye.

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