Home
Class 12
PHYSICS
A body of mass 8 kg is hanging another b...

A body of mass 8 kg is hanging another body of mas 12 kg. The combination is being pulled by a string with an acceleration of `2.2 m s^(-2)` . The tension `T_(1) and T_(2)` will be respectively: (use `g = 9.8 m//s^(2)` ) :

A

200 N, 80 N

B

220 N, 90 N

C

240 N, 96 N

D

960 N, 96 N

Text Solution

Verified by Experts

The correct Answer is:
C

`T_(2)-80=8(2.2)" ……………(i)"`
`T_(1)-T_(2)-120=12(2.2)" ………………..(ii)"`
`T_(1)=240N, T_(2)=96N`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • DRILL TEST 2

    NEET MAJOR TEST (COACHING)|Exercise PHYSICS|42 Videos
  • DRILL TEST 6

    NEET MAJOR TEST (COACHING)|Exercise PHYSICS|25 Videos

Similar Questions

Explore conceptually related problems

The masses M_(1), M_(2) and M_(3) are 5, 2 and 3 kg respectively. These have been joined using massless, inextensible pieces of strings as shown in the figure. If the whole system is going upward with an acceleration of 2ms^(-2) , then the value of tensions T_(1), T_(2) and T_(3) respectively are ["take "g=9.8ms^(-2)]

In the figure shown ,find : (g = 10 m//s^(2)) (a) acceleration of 1 kg,2 kg and 3 kg blocks and (b) tension T_(1) and T_(2) .

Knowledge Check

  • A body of mass 8 kg is hanging from another body of mass 12 kg. The combination is being pulled up by a string with an acceleration of 2.2 m/sec2. The tension T1 will be -

    A
    260N
    B
    240N
    C
    220N
    D
    200N
  • The mass of lift is 500 kg. When it ascends with an acceleration of 2m//s^(2) ,the tension in the cable will be [g=10m//s^(2)]

    A
    6000 N
    B
    5000 N
    C
    4000 N
    D
    50 N
  • A lift of mass 100 kg is moving upwards with an acceleration of 1 m//s^(2) . The tension developed in the string, which is connected to lift is ( g=9.8m//s^(2) )

    A
    980 N
    B
    1080 N
    C
    1100 N
    D
    1000 N
  • Similar Questions

    Explore conceptually related problems

    A body of mass 1.0 kg is falling with an acceleration of 10 m//s^(2) . Its apparent weight will be (g=10m//sec^(2))

    The apparent weight of the body, when it is travelling upwards with an acceleration of 2m//s^(2) and mass is 10 kg , will be

    The frictional force of the air on the body of mass 0.25kg, falling with an acceleration of 9.2 m//s^(2) will be (g=9.8m//s^(2)) .

    A wooden block of mass 1kg and density 800 Kg m^(-3) is held stationery, with the help of a string, in a container filled with water of density 1000 kg m^(-3) as shown in the figure. If the container is moved upwards with an acceleration of 2 m s^(-2) , then the tension in the string will be ( take g=10ms^(-2) )

    The mass of a lift is 500 kg. What will be the tension in its cable when it is going up with an acceleration of 2.0 m//s^(2) ? (Take, g = 9.8 m//s^(2) )