The strength of bonds by overlapping of atomic orbitals is in order

Options

A. `s - s gt s - p gt p - p`
B. `s - s gt s - p gt s - p`
C. `s - p gt s - s gt p - p`
D. `p - p gt s - s gt s - p`

Explanation

To determine the strength of bonds formed by overlapping atomic orbitals, we can analyze the types of overlaps: SS, SP, and PP. The strength of these bonds is influenced by the percentage of S-character in the hybridization of the orbitals involved.

### Step-by-Step Solution:

1. **Understanding Orbital Overlaps**:
- **SS Overlap**: This occurs when two s orbitals overlap. Since s orbitals have 100% s-character, this type of bond is expected to be the strongest.
- **SP Overlap**: This occurs when one s orbital overlaps with one p orbital. The hybridization here has 50% s-character and 50% p-character, making it stronger than the PP overlap but weaker than the SS overlap.
- **PP Overlap**: This occurs when two p orbitals overlap. Since p orbitals have 0% s-character, this bond is the weakest among the three.

2. **Ranking the Bond Strengths**:
- Based on the percentage of s-character:
- SS overlap has 100% s-character (strongest).
- SP overlap has 50% s-character (intermediate strength).
- PP overlap has 0% s-character (weakest).
- Therefore, the order of bond strength from strongest to weakest is: **SS > SP > PP**.

3. **Conclusion**:
- The final order of bond strength based on the overlapping of atomic orbitals is:
- **SS > SP > PP**.