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A simplified applified of MO theory to t...

A simplified applified of `MO` theory to the hypotheritical molecule `OF` would gives its bond order as:

A

2

B

1.5

C

`1.0`

D

`0.5`

Text Solution

Verified by Experts

The correct Answer is:
B
`OF` is derivavtive of `O_(2)` and isoelectronic with `O_(2)^(-)`
So `(sigma 1*s)^(2) (sigma 2s)^(2) (sigma*2s)^(2) (sigma 2p_(z)^(2) = pi 2p_(y)^(2)) (pi*2p_(s)^(2) = pi *2p_(y)^(1))`
The bond order of `1//2 (10-7) = 1.5`
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Knowledge Check

  • The molecule which has highest bond order is

    A
    `C_2`
    B
    `N_2`
    C
    `B_2`
    D
    `O_2`

  • Which charge for the N_2 molecule would give a bond order of 2.5 ?

    A
    `+1`
    B
    `+2`
    C
    `-1`
    D
    `-2`

  • The molecule having bond order 3 is

    A
    `H_2`
    B
    `N_2`
    C
    `O_2`
    D
    `He_2^(+)`

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