Home
Class 12
MATHS
The ratio of the sides of a triangle ABC...

The ratio of the sides of a triangle ABC is `1: sqrt3:2.` Then the ratio `A:B:C` is-

A

`3:5:2`

B

`1:2:3`

C

`1:sqrt3:2`

D

`3:2:1`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MCQ's

    CHHAYA PUBLICATION|Exercise QUESTION PAPER 3|90 Videos
  • MCQ's

    CHHAYA PUBLICATION|Exercise QUESTION PAPER 5|89 Videos
  • MCQ's

    CHHAYA PUBLICATION|Exercise QUESTION PAPER 32|1 Videos
  • MCQ ZONE 3

    CHHAYA PUBLICATION|Exercise Question Paper 8|30 Videos
  • Measures of Central Tendency

    CHHAYA PUBLICATION|Exercise Exercise 2 C Very short answer type question|18 Videos

Similar Questions

Explore conceptually related problems

If the ratio of three sides of a triangle be sqrt(2) : sqrt(3) : sqrt(5) , then the triangle is always a right-angled triangle.

The sides of a triangle are in the ratio 1: sqrt3:2. Then the angles are in the ratio

Knowledge Check

  • If the ratio of the length of the sides of a triangle be 1:sqrt3:2 then the ratio of the angle be

    A
    1:3:5
    B
    1:2:3
    C
    2:3:1
    D
    2:3:4
  • In triangle ABC, If cos B= a/(2c) , then the triangle is-

    A
    equilateral
    B
    isosceles
    C
    right angled
    D
    scalene.
  • If the sides of the triangle ABC are p,q and sqrt(p^(2)+ pq+q^(2)), then the greatest angle of the triangle is-

    A
    `(pi)/(2)`
    B
    `(2pi)/(3)`
    C
    `(5pi)/(4)`
    D
    `(5pi)/(3)`
  • Similar Questions

    Explore conceptually related problems

    If the angles of a triangle are in ratio 1 : 1 : 2, then the ratio of the sides of the triangle is

    A(0,sqrt(2))andB(2sqrt(2),0) are two vertices of a triangle ABC and AB=BC . If the equation of the side BC be x=2sqrt(2) , then the area of triangle ABC is (in sq . Units )-

    In a triangle ABC, if (sqrt3-1)a = 2b, A = 3B , then /_C is

    If in a triangle ABC, b sin B = c sin C, then the triangle is-

    If in triangle ABC,cot(A/2)=(b+c)/a, then the triangleABC is