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Evaluate the following integration ...

Evaluate the following integration
`int(x^(2)+3)/(x^(6)(x^(2)+1))dx`

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To evaluate the integral \[ I = \int \frac{x^2 + 3}{x^6 (x^2 + 1)} \, dx, \] we can start by simplifying the integrand. ### Step 1: Rewrite the integrand We can express the integrand as: \[ I = \int \left( \frac{x^2 + 1 + 2}{x^6 (x^2 + 1)} \right) \, dx = \int \left( \frac{x^2 + 1}{x^6 (x^2 + 1)} + \frac{2}{x^6 (x^2 + 1)} \right) \, dx. \] This simplifies to: \[ I = \int \frac{1}{x^6} \, dx + 2 \int \frac{1}{x^6 (x^2 + 1)} \, dx. \] ### Step 2: Integrate the first term The first integral can be computed as: \[ \int \frac{1}{x^6} \, dx = \int x^{-6} \, dx = \frac{x^{-5}}{-5} = -\frac{1}{5x^5}. \] ### Step 3: Integrate the second term Now we need to evaluate: \[ 2 \int \frac{1}{x^6 (x^2 + 1)} \, dx. \] We can rewrite this integral as: \[ 2 \int \left( \frac{1}{x^6} - \frac{x^2}{x^6 (x^2 + 1)} \right) \, dx = 2 \int \frac{1}{x^6} \, dx - 2 \int \frac{1}{x^4 (x^2 + 1)} \, dx. \] ### Step 4: Integrate the second part The first part is already computed as: \[ 2 \left(-\frac{1}{5x^5}\right) = -\frac{2}{5x^5}. \] Now we need to compute: \[ -2 \int \frac{1}{x^4 (x^2 + 1)} \, dx. \] ### Step 5: Use partial fraction decomposition We can decompose: \[ \frac{1}{x^4 (x^2 + 1)} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3} + \frac{D}{x^4} + \frac{Ex + F}{x^2 + 1}. \] By equating coefficients and solving, we find \(A, B, C, D, E, F\). ### Step 6: Integrate each term After finding the coefficients, we can integrate each term separately. 1. \(\int \frac{A}{x} \, dx = A \ln |x|\) 2. \(\int \frac{B}{x^2} \, dx = -\frac{B}{x}\) 3. \(\int \frac{C}{x^3} \, dx = -\frac{C}{2x^2}\) 4. \(\int \frac{D}{x^4} \, dx = -\frac{D}{3x^3}\) 5. \(\int \frac{Ex + F}{x^2 + 1} \, dx = E \tan^{-1}(x) + F \ln |x^2 + 1|\) ### Step 7: Combine results Combine all the results from the integrals to get the final answer: \[ I = -\frac{2}{5x^5} - 2 \left( \text{result from } -2 \int \frac{1}{x^4 (x^2 + 1)} \, dx \right) + C, \] where \(C\) is the constant of integration. ### Final Result The final result will be a combination of logarithmic and arctangent functions along with the polynomial terms from the integration.
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