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Molarity: A solution contains 3.65g of h...

Molarity: A solution contains `3.65g` of hydrogen chloride `(HCl)` in `2.00L` of sollution. Calculate the molarity `(M)` of the solution.
Strategy: Convert grams of `HCl` to moles of `HCl` and then apply Eq(1.20).

Text Solution

Verified by Experts

Step 1: Calculate the moles of solute `(HCl):`
Number of moles of `HCl (n_(HCl)) = ("Mass Of HCl")/("Molar mass of HCl")`
`n_(HCl) = (3.65g)/(36.5g mol^(-1)) = 1.100 mol HCI`
Step 2: Apply the definition of molartiy using Eq (1.20)
`M = ("Molar of solute")/("Liners of soln".) = 0.050 "mol" HCl L^(_1) soln`
or `0.50 "mol" L^(-1)`
Alternatelty, in one setup,
`(? "mol" HCl)/(L soln) = (3.65 g HCl)/(2.00 "L soln") xx (1 "mol" HCl)/(36.5 g HCl) = 0.050 "mol" L^(-1)`
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Knowledge Check

  • The molarity of a solution obtained by mixing 800 ml of 0.5 M HCl with 200 ml of 1 M HCl will be

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  • The molarity of a solution obtained by mixing 750 mL of 0.5 M HCl with 250 ml of 2 M HCl will be

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