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The total number of electrons present in...

The total number of electrons present in all `s` orbitals, all the `p` orbitals, and all the `d` orbitals of cesium ion are, respectively,

A

`8, 26, 10`

B

`10, 24, 20`

C

`8, 22, 24`

D

`12, 20, 22`

Text Solution

Verified by Experts

The correct Answer is:
B

The atomic numbe rof cseium is `55`. Therefore, its ground state electron configuration is
`1s^(2)2s^(2)2p^(6)3s^(6)3d^(10)4s^(2)4d^(6)4d^(10)5s^(2)5p^(6)6s^(1)`
or simply, `[Xe] 6s^(1)`
`Cs^(+)` ion will have `Xe` configuration.
Eletron present in the `s` subshell `= 5xx2 = 10`
Electrons present in the `p` subshell `= 4 xx 6 = 24`
Electron present in the `d` subshell `= 10 xx2 = 20`
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Knowledge Check

  • The maximum number of electrons present in any orbit will be

    A
    `n^(2) `
    B
    `2n^(2) `
    C
    `2n`
    D
    None of these
  • The maximum number of electrons present in an orbit. l = 3 , is .

    A
    6
    B
    8
    C
    10
    D
    14
  • The maximum number of unpaired electrons can present in p_(x) orbital is

    A
    0
    B
    1
    C
    2
    D
    3
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