The total number of electrons present in all `s` orbitals, all the `p` orbitals, and all the `d` orbitals of cesium ion are, respectively,

Options

A. `8, 26, 10`
B. `10, 24, 20`
C. `8, 22, 24`
D. `12, 20, 22`

Answer

B

Explanation

The atomic numbe rof cseium is `55`. Therefore, its ground state electron configuration is
`1s^(2)2s^(2)2p^(6)3s^(6)3d^(10)4s^(2)4d^(6)4d^(10)5s^(2)5p^(6)6s^(1)`
or simply, `[Xe] 6s^(1)`
`Cs^(+)` ion will have `Xe` configuration.
Eletron present in the `s` subshell `= 5xx2 = 10`
Electrons present in the `p` subshell `= 4 xx 6 = 24`
Electron present in the `d` subshell `= 10 xx2 = 20`