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In a Daniell cell, when a Za electrode a...

In a Daniell cell, when a Za electrode and a Cu electrode ane connected with a wire

A

electrons flow from the Zn electrode to the Cu electrode through the wire

B

electrons flow from the Cu electrode to the Zn electrode through the wire

C

current flow from the Zn electrode to the cu electrode through the wire

D

electrons flow from the Zn electrode to the cu electrode through the cell

Text Solution

Verified by Experts

The correct Answer is:
A
Electrons are released (by oxidation) at the anode (Zn electrode ) and consumed (by reduction) at the cathode (Cu electrode). Therefore, electrons flow through thewire from anode to cathode, i.e., in all voltaic cells, the electrons flow spontaneously from the negative electrode to the positive electrode.
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In a Daniell cell, electrons flow from zinc electrode to copper electrode outside the cell.

The e.m.f. of the cell obtained by combining Zn and Cu electrode of a Daniel cell with N calomel electrode in two different arrangements are 1.083V and 0.018V respectively at 25^(@)C . If the standard reduction potential of N calomel electrode is 0.28V find the emf og Daniel cell.

Knowledge Check

  • The passage of electricity in the Daniell cell when Zn and Cu electrodes are connected is from :

    A
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    B
    Cu to Zn outside the cell
    C
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    D
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  • In a voltaic cell, if iron and silver electrodes are connected with each other then current flow

    A
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    C
    from silver to iron outside the cell
    D
    current does not flow in this cell

  • In a cell of normal hydrogen electrode and calomel electrode, the electrode reaction taking place at calomel electrode will be

    A
    `Hg_2CI_(2(s))to2Hg_((I))+2CI^(-)+2e^(-)`
    B
    `2Hg_((I))+2CI^(-)toHg_2CI_(2(s))+2e^(-)`
    C
    `Hg_2CI_(2(s))+2e^(-)to2Hg_((I))+2CI^(-)`
    D
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