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6.02xx10^(20) molecules of urea are pres...

`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:

A

`0.1 M`

B

`0.001 M`

C

`0.1 M`

D

`0.02 M`

Text Solution

Verified by Experts

The correct Answer is:
A
Number of moles (urea)
`= (6.02xx10^(20) "molecules")/(6.02xx10^(23) "molecules" mol^(-1))`
`= 0.01 mol`
Volume of soltuion in liters `= (100 mL)/(1000 mL L^(-1)) = 0.1L`
Molarity `= ("Number of moles")/("Volume in liters") = (0.01 mol)/(0.1) = 0.01M`
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