`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:

Options

A. `0.1 M`
B. `0.001 M`
C. `0.1 M`
D. `0.02 M`

Answer

A

Explanation

Number of moles (urea)
`= (6.02xx10^(20) "molecules")/(6.02xx10^(23) "molecules" mol^(-1))`
`= 0.01 mol`
Volume of soltuion in liters `= (100 mL)/(1000 mL L^(-1)) = 0.1L`
Molarity `= ("Number of moles")/("Volume in liters") = (0.01 mol)/(0.1) = 0.01M`