An organic compound decolorizes `Br_2` water and also gives red ppt. with `Cu_2Cl_2` solution the compound is

Options

A. `CH_2=CH_2`
B. `CH_3CH=CH_2`
C. `CH_3C-=CH`
D. `CH_3C-=C CH_3`

Explanation

To solve the problem, we need to identify the organic compound that decolorizes bromine water and gives a red precipitate with cuprous chloride (Cu₂Cl₂).

### Step-by-Step Solution:

1. **Understanding the Reactions**:
- The first reaction involves the decolorization of bromine water. This indicates that the compound is likely unsaturated, meaning it contains either a double or triple bond (alkenes or alkynes).
- The second reaction involves the formation of a red precipitate with cuprous chloride, which is characteristic of terminal alkynes.

2. **Identifying Unsaturated Compounds**:
- Unsaturated compounds can be alkenes or alkynes. Alkenes will decolorize bromine water due to the addition reaction across the double bond. Alkynes can also decolorize bromine water, especially terminal alkynes.

3. **Understanding the Red Precipitate**:
- The formation of a red precipitate with Cu₂Cl₂ is a specific test for terminal alkynes. Terminal alkynes react with cuprous chloride to form a red precipitate of cuprous alkyne ions.

4. **Evaluating Options**:
- If we have multiple options (let's say A, B, C, D), we need to evaluate each one:
- **Option A**: If it is an alkyne but not terminal, it will decolorize bromine but not give a red precipitate.
- **Option B**: Similar to option A, if it is an internal alkyne, it will also decolorize bromine but not give a red precipitate.
- **Option C**: If it is a terminal alkyne, it will decolorize bromine and give a red precipitate with Cu₂Cl₂.
- **Option D**: If it is an alkyne but not terminal, it will behave like A and B.

5. **Conclusion**:
- The only compound that meets both criteria (decolorizing bromine water and giving a red precipitate with Cu₂Cl₂) is a terminal alkyne. Therefore, the answer to the question is **C**, which represents a terminal alkyne.

### Final Answer:
The compound is a **terminal alkyne** (Option C).