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In the reaction below, X is Neopentyl ...

In the reaction below, `X` is
Neopentyl alcohol `overset(H_(2)SO_(4))rarrX`

A

`2`-methylpentane

B

`2`-methylpent-`2`-ene

C

`2`-methybut-`2`-ene

D

Neopentane

Text Solution

Verified by Experts

The correct Answer is:
C

Initially formed carbocation undergoes rearrangement to form unexpected alkene.
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In the reaction given below, the product C is CaC_(2)overset(H_(2)O)rarr A overset("Dil. "H_(2)SO_(4))underset(HgSO_(4))rarrBoverset(H_(2)//Ni)rarrC

Knowledge Check

  • In the reaction given below, X is Neopentyl alcohol overset(H_(2)SO_(4))(rarr)X

    A
    `2-`methylpentane
    B
    `2-`methylpent-2-ene
    C
    `2-`methylbut`-2-`ene
    D
    neopentane
  • In the reaction below, X is Neopentyl alcohol overset(H_2SO_4)to X

    A
    2-methylpentane
    B
    2-methylpent-2-ene
    C
    2-methylbut-2-ene
    D
    neopentane
  • In the reaction given below, X is Neo-pentyl alcohol overset(H_(2)SO_(4))to X

    A
    2-methypentane
    B
    2-methylpent-2-ene
    C
    2-methylbut-2-ene
    D
    Neo-pentane
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