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What is the shape of Fe(CO)(5) molecule ...

What is the shape of `Fe(CO)_(5)` molecule ? Given that its dipole moment = 0.

A

octahedral

B

square planar

C

trigonal bipyramidal

D

square bipyramidal

Text Solution

Verified by Experts

The correct Answer is:
C
In `[Fe(CO)_(5)]` the oxidation number of Fe is zero `Fe^(0) (3d^(6) 4d^(2))` Since CO is a strong field ligand, the electron configuration is resuffled so as to provide one vacant d orbital for `dsp^(3)` hybrization leaging to trigonal bipyramidal geometry as well as shape.
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