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What is the shape of Fe(CO)(5) molecule ...

What is the shape of `Fe(CO)_(5)` molecule ? Given that its dipole moment = 0.

A

octahedral

B

square planar

C

trigonal bipyramidal

D

square bipyramidal

Text Solution

Verified by Experts

The correct Answer is:
C
In `[Fe(CO)_(5)]` the oxidation number of Fe is zero `Fe^(0) (3d^(6) 4d^(2))` Since CO is a strong field ligand, the electron configuration is resuffled so as to provide one vacant d orbital for `dsp^(3)` hybrization leaging to trigonal bipyramidal geometry as well as shape.
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Knowledge Check

  • Shape of Fe(CO)_(5) is:

    A
    Octahedral
    B
    Square planar
    C
    Trigonal bipyramidal
    D
    Square pyramidal

  • The molecule which have zero dipole moments is .

    A
    `CH_(2)CI_(2)`
    B
    `BF_(3)`
    C
    `NF_(3)`
    D
    `CIO_(2)`

  • The molecule which has zero dipole moment is

    A
    `CH_(2) CI_(2)`
    B
    `BF_(3)`
    C
    `NF_(3)`
    D
    `CIO_(2)`

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