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The number of geometrical isomers for [P...

The number of geometrical isomers for `[Pt(NH_(3))_(2)CI_(2)]` is

A

3

B

4

C

1

D

2

Text Solution

Verified by Experts

The correct Answer is:
D
In a square planar complex of formula `[MX_(2)L_(2)]` , where X and L are two different unidentate ligands, the two ligands X or L may be arranged adjacent to each other in a cis isomer, or opposite or each other in a trans isomer as depicted below:
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Draw the geometrical isomers of complex [Pt(NH_(3))_(2)Cl_(2)] .

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Knowledge Check

  • The number of geometrical isomers for [P(NH_(3))_(2)Cl_(2)] is

    A
    2
    B
    1
    C
    3
    D
    4

  • The number of geometrical isomers for [Pt(NH_3)_2Cl_2] is

    A
    (a) Two
    B
    (b) One
    C
    (c) Three
    D
    (d) Four

  • The number of geometrical isomers of [Co(NH_(3))_(3)(NO_(2))_(3)] are

    A
    4
    B
    3
    C
    2
    D
    0

    • Similar Questions

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    The number of geometrical isomers of [Co(NH_(3))_(3)(NO_(3))_(3)] are :

    The number of geometrical isomers of [Co(NH_(3))_(3)(NO_(3))_(3)] are :

    The number of geometrical isomers of [CrCl_(2)(en)(NH_(3))_(2)] , where en= ethylene diamine, is -

    The number of geometrical isomers possible for [Pt(NO_(2))(NH_(3))(NH_(2)OH)(Py)]^(+)

    The number of geometrical isomers of [Co(NH_3)_3(NO_3)_3] are:

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