One end of a light spring constant `k` and natural length `l_(0)` is fixed and the other end is attached to a block of mass `m` lying on smooth horizontal surface. If the block is rotating in the horizontal circle of radius `l`, find the frequency of the revolution.

Explanation

Extension of spring `x=l-l_(0)`
Here, the necessary centripetal force is provide by the spring force `kx`
`kx=momega^(2)l`
`k(l-l_(0)=m omega^(2)l`
`omega=sqrt((k(l-l_(0)))/(ml))`
`2pif=sqrt((k(l-l_(0)))/(ml))`
`f=(1)/(2pi)sqrt((k(l-l_(0)))/(ml))`
where `f` is the frequency of revolution.