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In making an alloy, a substance of speci...

In making an alloy, a substance of specific gravity `s_(1)` and mass `m_(1)` is mixed with another substance of specific gravity of the alloy is

A

`((m_1 + m_2)/(s_1 + s_2))`

B

`((s_1 s_2)/(m_1 + m_2))`

C

`(m_1 + m_2)/((m_1)/(s_1) + (m_2)/(s_2))`

D

`((m_1)/(s_1) + (m_2)/(s_2))/(m_1 + m_2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`S = (m_1+ m_2)/(V_1 + V_2) = (m_1 + m_2)/((m_1)/(s_1) + (m_2)/(s_2))`.
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Knowledge Check

  • In making an alloy, a substance of specific gravity s_(1) and mass m_(1) is mixed with another substance of specific gravity s_(2) mass m_(2) , then the specific gravity of the alloy is

    A
    `((m_(1) + m_(2))/( s_(1) + s_(2)))`
    B
    `(( s_(1) s_(2))/( m_(1) + m_(2)))`
    C
    `((m_(1) + m_(2))/( m_(1) // s_(1) + m_(2) // s_(2)))`
    D
    `(( m_(1) // s_(1) + m_(2) // s_(2))/(m_(1) + m_(2)))`

  • wood with specific gravity of less than 0.2 is

    A
    bombax
    B
    populus
    C
    ochroma
    D
    Olea.

  • 150 ml of a solution containing 5 millimoles of A (specific gravity = 1.2 ) is mixed with 250 ml of another solution containing 10 millimoles of A (specific gravity = 1.4 ). If on mixing the density of the solution becomes (5.3)/(4.5)gm//ml , then what will be molartiy of A in the final solution?

    A
    `(1)/(30)M`
    B
    `(3)/(80)M`
    C
    `(1)/(20)M`
    D
    `(4)/(85)`
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