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Pressure exerted by a perfect gas equal ...

Pressure exerted by a perfect gas equal to

A

mean `K.E.` per unit volume

B

half of mean `K.E.` per unit volume

C

one-third of mean `K.E.` per unit volume

D

two-third of mean `K.E.` per unit volume

Text Solution

Verified by Experts

The correct Answer is:
D
`P = (1)/(3) (M)/(V) v_(rms)^(2) = (2)/(3)(((1)/(2)Mv_(rms)^(2))/(V))`
`= (2 K)/(3V), K :K.E`.
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Knowledge Check

  • According to the kinetic theory of gasses pressure exerted by perfect gas molecule on the wall of a container is equal to momentum transferred to the wall per unit area

    A
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    per second by only molecules
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    D
    directly proportional to the square of the density of the gas

  • Perfect gas equation

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    `PV = T/R`
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    `PV = RT`
    D
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