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Pressure exerted by a perfect gas equal ...

Pressure exerted by a perfect gas equal to

A

mean `K.E.` per unit volume

B

half of mean `K.E.` per unit volume

C

one-third of mean `K.E.` per unit volume

D

two-third of mean `K.E.` per unit volume

Text Solution

Verified by Experts

The correct Answer is:
D

`P = (1)/(3) (M)/(V) v_(rms)^(2) = (2)/(3)(((1)/(2)Mv_(rms)^(2))/(V))`
`= (2 K)/(3V), K :K.E`.
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CP SINGH-KINETIC THEORY OF GASES-Exercises
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  3. Pressure exerted by a perfect gas equal to

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  5. According to the kinetic theory of gases, at absolute temperature

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  6. Gas at a pressure P(0) in contained as a vessel. If the masses of all ...

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  7. Three containes of the same volume contain three different gases. The ...

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  8. Four molecules have speeds 2 m//s, 3 km//s, 4 km//s and 5 km//s. The r...

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  9. Speed of sound in a gas is v and rms velocity of the gas molecules is ...

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  10. The mean square speed of the molecules of a gas at absolute temperatur...

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  11. At room temperature, the rms speed of the molecules of a certain diato...

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  12. Which of the following gases has maximum rms speed at a given temperat...

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  13. The temperature at which the rms speed of air molecules is double of t...

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  14. The curve between absolute temperature and v(rms)^(2) is

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  15. The rms speed of oxygen molecules in a gas is v. If the temperature is...

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  16. A mixture of 2 moles of helium gas ((atomic mass)=4a.m.u) and 1 mole o...

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  17. For gas at a temperature T the root-mean-square speed v(rms), the most...

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  18. The root mean square velocity of hydrogen molecules at 300 K is 1930 m...

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  19. The root mean square velocity of the molecules in a sample of helium i...

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