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1 kg of ice at 0^@C is mixed with 1 kg o...

1 kg of ice at `0^@C` is mixed with 1 kg of steam at `100^@C`
(i) The equilibrium temperature is `100^@C`
(ii) The equilibrium temperature is `0^@C`
(iii) The contents of mixture are : 665 g steam, 1335 g water
(iv) The contents of mixture are 800 g steam, 1200 g water

A

(i),(iii)

B

(ii),(iii)

C

(i),(iv)

D

(ii),(iv)

Text Solution

Verified by Experts

The correct Answer is:
A
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Knowledge Check

  • 1 kg ice at -20^(@)C is mixed with 1 kg steam at 200^(@)C . The equilibrium temperature and mixture content is

    A
    `80^(@)C`, and mixture content `2 kg`
    B
    `110^(@)C`, and mixture content `2 kg` steam
    C
    `100^(@)C`, and mixture content `(10)/(17) kg` steam and `(24)/(17) kg` water
    D
    `100^(@)C`, and mixture content `(20)/(27) kg` steam and `(34)/(27) kg`

  • 2g ice at 0^(@)C is mixed with 1 g steam at 100^(@)C . Find the final temperature of the mixture.

    A
    `0^(@)C`
    B
    `50^(@)`
    C
    `100^(@)C`
    D
    `gt100^(@)C`

  • 1g of ice at 0^@ C is mixed 1 g of steam at 100^@ C . The mass of water formed is

    A
    `1.33 g`
    B
    `1 g`
    C
    `0.133 g`
    D
    `13.3 g`

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