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A ball is dropped from the top of a towe...

A ball is dropped from the top of a tower. The ratio of work done by force of gravity in `1^(st), 2^(nd)`, and `3^(rd)` second of the motion of ball is

A

`1:2:3`

B

`1:4:16`

C

`1:3:5`

D

`1:9:5`

Text Solution

Verified by Experts

The correct Answer is:
C
`W = FS rArr(W_(1))/(W_(2)) = (S_(1))/(S_(2)) = ((2n-1)_(1))/((2n-1)_(2))`
`(because S = u+a(n-(1)/(2)))`
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Knowledge Check

  • A ball is released from the top of a tower. The ratio of work done by force of gravity in 1st second, 2nd second and 3rd second of the motion of ball is

    A
    `1 : 2 : 3`
    B
    `1 : 4 : 16`
    C
    `1 : 3 : 5`
    D
    `1 : 9 : 25`

  • A ball is dropped from the roof of a tower height h . The total distance covered by it in the last second of its motion is equal to the distance covered by it in first three seconds. The value of h in metre is (g=10m//s^(2))

    A
    `125`
    B
    `200`
    C
    `100`
    D
    `80`

  • The ratio of the distance through which a ball falls in the 2^(nd), 3^(rd) and 4^(th) second is (the initial velocity of the ball is zero)

    A
    `3:5:7`
    B
    `4:5:6`
    C
    `4:9:16`
    D
    `5:7:9`

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