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For a first - order reaction, the rate o...

For a first - order reaction, the rate of reaction is `1.0xx10^(-2) mol L^(-1) s^(-1)` and the initial concentration of the reactant is 1 M. The half-life period for the reaction is

A

`6.93xx10^(-3)s^(-1)`

B

`0.693 s^(-1)`

C

`69.3 s`

D

`0.693 s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
Consider a simple general first order reaction `Ararr`products
Differential rate law is
`Rate=k[A]`
or `k=("Rate")/([A])=(1.0xx10^(-2)molL^(-1)s^(-1))/(1.0molL^(-1))`
`k10^(-2)s^(-1)`
For a first order reaction, half is given as
`t_(1//2)=(0.693)/(10^(-2))s^(-1))`
`=0.693xx10^(2)s`
`=69.3s`
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