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Chlorine on reaction with hot and concen...

Chlorine on reaction with hot and concentrated `NaOH` yields

A

`NaCl` and `NaCIO_(3)`

B

`NaCl` and `NaCIO`

C

`NaCl` and `NaCIO_(2)`

D

`NaCl` and `NaCIO_(4)`

Text Solution

Verified by Experts

The correct Answer is:
1
Chlorate are formed with hot and concentrated alkali solution :
`3Cl_(2)+6NaOH rarr 5NaClO_(3)+3H_(2)O`
It is disproportionate reactions as `Cl` from zero oxidation state is changed to `-1`and `+5` oxidation states:
`6Cl_(2)+underset("Hot and conc.")(6Ca(OH)_(2))rarr5CaCl_(2)+Ca(ClO_(3))_(2)+2H_(2)O`
Hypochlorities are formed with cold and dilute solution of alkali:
`Cl_(2)+2NaOH rarr NaCl+NaCIO+H_(2)O`
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Chlorine reacts with hot and concentrated NaOH and produces compounds (P) and (Q). Compound (P) gives white precipitate with silver nitrate solution. The average bond order between Cl and O atoms in (Q) is Report your answer up to two decimal places.

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Knowledge Check

  • Chlorine on reaction with hot and concentrated sodium hydroxide gives:

    A
    `ClO_3^-` and `ClO_2^-`
    B
    `Cl^-` and `ClO^-`
    C
    `Cl^-` and `ClO_3^-`
    D
    `Cl^-` and `ClO_2^-`

  • Chlorine on reaction with hot and concentrated sodium hydroxide gives :

    A
    `CI^(-) and CIO_(3)^(-)`
    B
    `CI^(-) and CIO^(-)`
    C
    `CIO_(3)^(-) and CIO_(2)^(-)`
    D
    `CI^(-) and CIO_(2)^(-)`

  • Chlorine react with hot and concentrated NaOH and produces compound (X) and (Y). Compound (X) gives white precipitate with silver nitrate solution. The average bond order between Cl and O atoms in (Y) is ___________.

    A
    1.67
    B
    `0.835`
    C
    2.67
    D
    2

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    Which of the following reactants on reaction with concentrated NaOH followed by acidification gives the following lactone as the only product

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