Home
Class 11
PHYSICS
A block of mass m sits at rest on a fric...

A block of mass `m` sits at rest on a frictionless table in a rail car that is moving with speed `v_(c)` along a straight horizontal track (fig.) A person riding in the car pushes on the block with a net horizontal force `F` for a time `t` in the direction of the car's motion.

What is the final speed of the block according to a person in the car ?

A

`(Ft)/(m)`

B

`(2Ft)/(m)`

C

`-(Ft)/(m)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A

`V = u + at = 0 + (Ft)/(m)`.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • WORK POWER AND ENERGY

    NARAYNA|Exercise Level-VI (Integer)|12 Videos
  • WORK POWER AND ENERGY

    NARAYNA|Exercise Level-VI (Multiple Answer)|11 Videos
  • WORK , ENERGY & POWER

    NARAYNA|Exercise EXERCISE IV|43 Videos

Similar Questions

Explore conceptually related problems

Three identical blocks, each having a mass m are pushed by a force F on the Frictionless table as shown in figure. What is the net force on the block A?

A block of mass m is stationary with respect to the wedge of mass M moving with uniform speed v on horizontal surface. Work done by friction force on the block in t seconds is

Knowledge Check

  • A block of mass m sits at rest on a frictionless table in a rail car that is moving with speed v_(c) along a straight horizontal track (fig.) A person riding in the car pushes on the block with a net horizontal force F for a time t in the direction of the car's motion. How much did K.E of the block change according to the person in the car ?

    A
    `(F^(2)t^(2))/(2m)`
    B
    `(F^(2) t^(2))/(m)`
    C
    `(2F^(2)t^(2))/(m)`
    D
    None of these
  • A block of mass m sits at rest on a frictionless table in a rail car that is moving with speed v_(c) along a straight horizontal track (fig.) A person riding in the car pushes on the block with a net horizontal force F for a time t in the direction of the car's motion. According to the person on the ground. The change in KE of block is

    A
    `(m(V_(c)+(Ft)/(m))^(2))/(2)-(mv_(c)^(2))/(2)`
    B
    `(m(V_(c)+(Ft)/(m))^(2))/(2)+(mv_(c)^(2))/(2)`
    C
    `(mv_(c)^(2))/(2) -(m(V_(c)+(Ft)/(m))^(2))/(2)`
    D
    None of these
  • A block of mass m sits at rest on a frictionless table in a rail car that is moving with speed v_(c) along a straight horizontal track (fig.) A person riding in the car pushes on the block with a net horizontal force F for a time t in the direction of the car's motion. According to the person on the ground. The displacement of block is

    A
    `(Ft^(2))/(2m) +2v_(c)t`
    B
    `(Ft^(2))/(2m) +v_(c)t`
    C
    `(Ft^(2))/(m)+ v_(c) t`
    D
    `(Ft^(2))/(2m) -v_(c) t`
  • Similar Questions

    Explore conceptually related problems

    Calculate the work done by a car against gravity in moving along a straight horizontal road. The mass of the car is 400 kg and the distance moved is 2m.

    A block of mass m sits at rest on a frictionless table in a rail car that is moving with speed v_(c) along a straight horizontal track (fig.) A person riding in the car pushes on the block with a net horizontal force F for a time t in the direction of the car's motion. According to a person standing on the ground outside the train ?

    A block of mass m sits at rest on a frictionless table in a rail car that is moving with speed v_(c) along a straight horizontal track (fig.) A person riding in the car pushes on the block with a net horizontal force F for a time t in the direction of the car's motion. In terms of F,m & t , how far did the the force displace the object according to the person in car ?

    A block of mass 70kg is kept on a rough horizontal surface (mu=0.4) . A person is trying to pull the block by applying a horizontal force, but the block is not moving. The net contact force exerted by the surface on the block is F , then:

    A block of mass 70 kg is kept on a rough horizontal surface (mu = 0.4). A person is trying to pull the block is not moving. The net contact force exerted by the surface on the block is F, then :