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A large slab of mass 5kg lies on a smoot...

A large slab of mass `5kg` lies on a smooth horizontal surface, with a block of mass `4kg` lying on the top of it. The coefficient of friction between the block and the slab is `0.25`. If the block is pulled horizontally by a force of F `=6N`, the work done by the force of friction on the slab, between the instants `t=2s` and `t=3s`, is `(g=10ms^-2)`

A

`2.4 J`

B

`5.55 J`

C

`4.444 J`

D

`10 J`

Text Solution

Verified by Experts

The correct Answer is:
`(2)`
Maximum frictional force between the slab and the block
`f_(max) = mu N = mumg` mass of upper block Evidently, F lt` f_(max)` so, the two bodies will move together as a single unit. If.a. be their combined acceleration, then `a = F/(m + M)` Therefore, frictional force acting can be obtained as `f= Ma`, Using s = `1/2 at^(2), find `S_(2)` and `S_(3)`,
`W = (S_(3)-S_(2))f`
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