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Consider following compounds A to E : ...

Consider following compounds A to E :
(A) `XeF_(n) " " (B) XeF_((n+1))^(+) " " (C ) XeF_((n+1))^(-) " " (D) XeF_((n+2))`
(E ) `XeF_((n+4))^(2-)`,
If value of n is 4, then calculate value of `p div q` here, 'p' is total number of bond pair and 'q' is total number of lone pair on central atoms of compounds (A) to (E ).

Text Solution

Verified by Experts

The correct Answer is:
4
`{:(,b.p.,1.p.),(XeF_(4),4,2),(XeF_(5)^(+),5,1),(XeF_(5)^(-),5,2),(XeF_(6),6,1),(XeF_(8)^(2-),8,1),(,28,7):}`
`implies (p)/(q)=(28)/(7)=04`
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Consider following compounds A to E: A: XeF_(n),B: XeF_((n+1))^(+), C : XeF_((n+1))^(-), D: XeF_((n+2)),E: Xe_((n+4))^(2-) If value of n is 4, then calculate value of p -: q here, p is total number of bond pair and q is total number of lone pair on central atoms of compound A to E

Number of lone pair of electrons in XeF_(4) is

Knowledge Check

  • Total number of electron pairs (both lone and bond pairs) around central atom of XeF_(4) is

    A
    4
    B
    6
    C
    5
    D
    7

  • The ratio of total number of lone pairs in XeF_2 and XeF_4 are:

    A
    `3:2`
    B
    `9:14`
    C
    `14:19`
    D
    `9:19`

  • The number of lone pairs on central atom in XeF_2, XeF_4 and XeF_6 are:

    A
    (A) 1,2,3
    B
    (B) 3,2,1
    C
    (C) 2,2,1
    D
    (D) 1,3,2

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