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The maximum number of photons emitted wh...

The maximum number of photons emitted when an electron jumps from an energy level `n=4` to `n=1` is

A

1

B

2

C

3

D

4

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To determine the maximum number of photons emitted when an electron jumps from an energy level \( n=4 \) to \( n=1 \), we can follow these steps: ### Step 1: Understand the Energy Levels In the Bohr model of the atom, electrons occupy discrete energy levels, denoted by quantum numbers \( n \). The electron can transition between these levels by absorbing or emitting energy in the form of photons. ### Step 2: Identify the Transition Levels In this case, the electron is transitioning from \( n=4 \) to \( n=1 \). However, it can also pass through intermediate energy levels during this transition. The possible intermediate levels are \( n=3 \) and \( n=2 \). ### Step 3: Calculate the Possible Transitions When an electron transitions from \( n=4 \) to \( n=1 \), it can do so in multiple steps: 1. From \( n=4 \) to \( n=3 \) 2. From \( n=3 \) to \( n=2 \) 3. From \( n=2 \) to \( n=1 \) Each of these transitions corresponds to the emission of one photon. Therefore, the maximum number of photons emitted during this transition is 3. ### Step 4: General Formula for Maximum Transitions For a general case where an electron transitions from a higher level \( n_2 \) to a lower level \( n_1 \), the maximum number of transitions (and thus photons emitted) can be calculated using the formula: \[ \text{Maximum transitions} = n_2 - n_1 \] In this case, \( n_2 = 4 \) and \( n_1 = 1 \), so: \[ \text{Maximum transitions} = 4 - 1 = 3 \] ### Conclusion Thus, the maximum number of photons emitted when an electron jumps from an energy level \( n=4 \) to \( n=1 \) is **3**. ---

To determine the maximum number of photons emitted when an electron jumps from an energy level \( n=4 \) to \( n=1 \), we can follow these steps: ### Step 1: Understand the Energy Levels In the Bohr model of the atom, electrons occupy discrete energy levels, denoted by quantum numbers \( n \). The electron can transition between these levels by absorbing or emitting energy in the form of photons. ### Step 2: Identify the Transition Levels In this case, the electron is transitioning from \( n=4 \) to \( n=1 \). However, it can also pass through intermediate energy levels during this transition. The possible intermediate levels are \( n=3 \) and \( n=2 \). ...
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Knowledge Check

  • The maximum number of photons emitted when an electron jumps from an energy level n=5 to n=1 is s

    A
    3
    B
    10
    C
    8
    D
    6
  • The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second orbit. Similarly, Paschen, Brackett and Pfund series are formed when electron returns to the third, fourth and fifth orbits from higher energy orbits respectively. Maximum number of lines produced when an electron jumps from nth level to ground level is equal to (n(n-1))/(2). For exampe, in the case of n=4, number of lines produced is 6 (4 to 3,4 t 2,4 to 1,3to 2,3 to 1,2 to 1). When an electron returns from n_(2) and n_(1) state, the number of lines in the spectrum will be equal to (n _(2)-n_(1))(n_(2)-n_(1) +1))/(2) If the electron comes back from energy level having energy E _(2) to energy level having energy E _(1), then the difference may be expressed in terms of energy of photon as : E_(2) -E_(1) =Delta E, lamda= (hc) /(Delta E) Since h and c are constants, Delta E corresponds to definite energy, thus each transition from one energy level to another will produce a light of definitewavelength. This is actually observed as a line in the spectrum of hydrogen atom. Wave number of line is given by the formula vecv=R((1)/(n _(1)^(2))-(1)/(n _(2) ^(2))), where R is a Rydberg's constant (R=1.1 xx 10 ^(7)m^(-1)) The energy photon emitted corresponding to transition n =3 to n =1 is [h=6 xx 10 ^(-34)J-sec]

    A
    `1.76 xx 10 ^(-18)J`
    B
    `1.98 xx 190 ^(-18)J`
    C
    `1.76 xx 10 ^(-17)J`
    D
    None of these
  • The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second orbit. Similarly, Paschen, Brackett and Pfund series are formed when electron returns to the third, fourth and fifth orbits from higher energy orbits respectively. Maximum number of lines produced when an electron jumps from nth level to ground level is equal to (n(n-1))/(2). For exampe, in the case of n=4, number of lines produced is 6 (4 to 3,4 t 2,4 to 1,3to 2,3 to 1,2 to 1). When an electron returns from n_(2) and n_(1) state, the number of lines in the spectrum will be equal to (n _(2)-n_(1))(n_(2)-n_(1) +(1)/(2) If the electron comes back from energy level having energy E _(2) to energy level having energy E _(1), then the difference may be expressed in terms of energy of photon as : E_(2) -E_(1) =Delta E, lamda= (hc) /(Delta E) Since h and c are constants, Delta E corresponds to definite energy, thus each transition from one energy level to another will produce a light of definitewavelength. This is actually observed as a line in the spectrum of hydrogen atom. Wave number of line is given by the formula vecv=R((1)/(n _(1)^(2))-(1)/(n _(2) ^(2))), where R is a Rydberg's constant (R=1.1 xx 10 ^(7)m^(-1)) In a collection of H–atom, electrons make transition from 5th excited state to 2nd excited state then maximum number of different types of photons observed are :

    A
    3
    B
    4
    C
    6
    D
    15
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    The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second orbit. Similarly, Paschen, Brackett and Pfund series are formed when electron returns to the third, fourth and fifth orbits from higher energy orbits respectively. Maximum number of lines produced when an electron jumps from nth level to ground level is equal to (n(n-1))/(2). For exampe, in the case of n=4, number of lines produced is 6 (4 to 3,4 t 2,4 to 1,3to 2,3 to 1,2 to 1). When an electron returns from n_(2) and n_(1) state, the number of lines in the spectrum will be equal to (n _(2)-n_(1))(n_(2)-n_(1) +(1)/(2) If the electron comes back from energy level having energy E _(2) to energy level having energy E _(1), then the difference may be expressed in terms of energy of photon as : E_(2) -E_(1) =Delta E, lamda= (hc) /(Delta E) Since h and c are constants, Delta E corresponds to definite energy, thus each transition from one energy level to another will produce a light of definitewavelength. This is actually observed as a line in the spectrum of hydrogen atom. Wave number of line is given by the formula vecv=R((1)/(n _(1)^(2))-(1)/(n _(2) ^(2))), where R is a Rydberg's constant (R=1.1 xx 10 ^(7)m^(-1)) The wave number of electromagnetic radiation emitted during the transition of electron in between two levels of Li ^(2+) ion whose principal quantum numbers sum is 4 and difference is 2 is:

    The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second orbit. Similarly, Paschen, Brackett and Pfund series are formed when electron returns to the third, fourth and fifth orbits from higher energy orbits respectively. Maximum number of lines produced when an electron jumps from nth level to ground level is equal to (n(n-1))/(2). For exampe, in the case of n=4, number of lines produced is 6 (4 to 3,4 t 2,4 to 1,3to 2,3 to 1,2 to 1). When an electron returns from n_(2) and n_(1) state, the number of lines in the spectrum will be equal to (n _(2)-n_(1))(n_(2)-n_(1) +(1)/(2) If the electron comes back from energy level having energy E _(2) to energy level having energy E _(1), then the difference may be expressed in terms of energy of photon as : E_(2) -E_(1) =Delta E, lamda= (hc) /(Delta E) Since h and c are constants, Delta E corresponds to definite energy, thus each transition from one energy level to another will produce a light of definitewavelength. This is actually observed as a line in the spectrum of hydrogen atom. Wave number of line is given by the formula vecv=R((1)/(n _(1)^(2))-(1)/(n _(2) ^(2))), where R is a Rydberg's constant (R=1.1 xx 10 ^(7)m^(-1)) The difference in the wavelength of the 1 ^(st) line of Lyman series and 2nd line of Balmer series in a hydrogen atom is :

    The total number of spectral lines obtained when an electron jumps, from n = 5 to n =1 in a sample of hydrogen atoms.

    the only electron in the hydrogen atom resides under ordinary conditions in the first orbit. When energy is supplied the electron moves to higher energy orbit depending on the amount of energy absorbed. It emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second. Similarly, Paschen, Breakett and Pfund series are formed when electron returns to the third, fourth and fifth orbits from higher energy orbits respectively (as shown in figure). Maximum number of different lines produced when electron jump from nth level to ground level is equal to (n(n-1))/(2). For example in the case of n=4, number of lines produced is 6.(4to3,4to2,4to1,3to2,3to1,2to1). When an electron returns from n_(2) "to"n_(1) state, the number of different lines in the spectrum will be equal to ((n_(2)-n_(1))(n_(2)-n_(1)+1))/(2) If the electron comes back from energy level having energy E_(2) to energy level having energy E_(1), then the difference may be expressed in terms of energy of photon as: E_(2)-E_(1)=DeltaE,lambda=(hc)/(DeltaE),DeltaE=hv(v-"frequency") Since h and c are constants DeltaE corresponds to definite energy: thus each transition from one energy level to another will produce a light of definite wavelength. This is actually observed as a line in the spectrum of hydrogen atom. Wave number of line is given by the formula: barv=RZ^(2)((1)/(n_(1)^(2))-(1)/(n_(2)^(2))) where R is a Rydberg constant (R=1.1xx10^(7)m^(-1)). (i) First line of a series : It is called line of longest wavelength of line of smallest energy'. (ii) Series limit or last line of a series : It is the line of shortest wavelength or line of highest energy. wave number of the first line of Paschen series in Be^(3+) ion is :

    the only electron in the hydrogen atom resides under ordinary conditions in the first orbit. When energy is supplied the electron moves to higher energy orbit depending on the amount of energy absorbed. It emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second. Similarly, Paschen, Breakett and Pfund series are formed when electron returns to the third, fourth and fifth orbits from higher energy orbits respectively (as shown in figure). Maximum number of different lines produced when electron jump from nth level to ground level is equal to (n(n-1))/(2). For example in the case of n=4, number of lines produced is 6.(4to3,4to2,4to1,3to2,3to1,2to1). When an electron returns from n_(2) "to"n_(1) state, the number of different lines in the spectrum will be equal to ((n_(2)-n_(1))(n_(2)-n_(1)+1))/(2) If the electron comes back from energy level having energy E_(2) to energy level having energy E_(1), then the difference may be expressed in terms of energy of photon as: E_(2)-E_(1)=DeltaE,lambda=(hc)/(DeltaE),DeltaE=hv(v-"frequency") Since h and c are constants DeltaE corresponds to definite energy: thus each transition from one energy level to another will produce a light of definite wavelength. This is actually observed as a line in the spectrum of hydrogen atom. Wave number of line is given by the formula: barv=RZ^(2)((1)/(n_(1)^(2))-(1)/(n_(2)^(2))) where R is a Rydberg constant (R=1.1xx10^(7)m^(-1)). (i) First line of a series : It is called line of longest wavelength of line of smallest energy'. (ii) Series limit or last line of a series : It is the line of shortest wavelength or line of highest energy. Last line of breakett series for H-atom has wavelength lambda_(1)"Å" and 2nd line of Lyman series has wavelength lambda_(2)"Å" then: