A particle moving along a circule path of radius 'r' with uniform angular velocity `omega`. Its angular acceleration is

Options

A. `r omega^(2)`
B. `r// omega`
C. zero
D. `omega//r`

Explanation

To solve the question regarding the angular acceleration of a particle moving along a circular path with uniform angular velocity, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Angular Velocity**:
- The problem states that the particle is moving with a uniform angular velocity, denoted as `ω`. This means that the angular displacement of the particle is changing at a constant rate over time.

2. **Definition of Angular Acceleration**:
- Angular acceleration (denoted as `α`) is defined as the rate of change of angular velocity with respect to time. Mathematically, it is expressed as:
\[ α = \frac{dω}{dt} \]
- Here, `dω` represents the change in angular velocity, and `dt` represents the change in time.

3. **Analyzing Uniform Angular Velocity**:
- Since the angular velocity `ω` is uniform, it does not change over time. This implies that:
\[ \frac{dω}{dt} = 0 \]
- Therefore, the angular acceleration `α` is zero because there is no change in angular velocity.

4. **Conclusion**:
- Based on the analysis, we conclude that the angular acceleration of the particle is:
\[ α = 0 \]

### Final Answer:
The angular acceleration of the particle is **0**.