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Statement I : Zn^(2+) is diamagnetic ...

Statement I : `Zn^(2+)` is diamagnetic
Statement II : The electrons are lost from 4s orbital to from `Zn^(2+)`

A

Statememt 1 is true, statement 2 is true , statement 2 is a correct explanation for statement 1

B

Statement 1 is true, statement 2 is true , statement 2 si not a correct explanation for statement 1

C

Statement 1 is true, statement 2 is false

D

Statement 1 is false, statement 2 is ture

Text Solution

Verified by Experts

The correct Answer is:
B
`Zn^(+)` is diamagnetic because it has no unpaired electrons.
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(a). Assertion (A) is true, Reason (R) is also true, Reason (R) is the correct explanation for assertion (A). (b). Assertion (A) is true, Reason (R) is true, Reason (R) is not the correct explanation for Assertion (A). (c). Assertion (A) is true, Reason (R) is false. (d). Assertion (A) is false, Reason (R) is true. Q. Assertion (A): Zn^(2+) is diamagnetic. Reason (R): The electrons are lost from 4s-orbital to form Zn^(2+) .

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Knowledge Check

  • Assertion : Fe^(2+) has 3de electronic configuration. Reason : Electrons are lost from 4s-orbital to form Fe^(2+) ion.

    A
    Assertion and reason both are correct statements and reason is correct explanation for assertion.
    B
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    C
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  • Statement-1:Dipositive zinc exhibits diamagnetism due to loss of two electrons from 3d-orbital of neutral atom. Statement-2:The electronic configuration of zinc (Z=30) is [Ar]^(18)3d^10 4s^2

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    B
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    C
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    D
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  • In the following set of questions, a Statement I is given and a corresponding Statement II is given below it. Mark the correct answer as: Statement I: In the solution of [Zn(OH)_(4)]^(2-) gradual addition of dil. HCl initially produces white the precipitate of Zn(OH)_(2) and on further addition of dil. HCl the white precipitate gets dissolved. Statement II: Zn(OH)_(2) is amphoteric in nature.

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