Transition metal compound are coloured d...

Transition metal compound are coloured due to `d-d` and charge transfer tranditoins, Colour due to `d-d` transition is shown by transition metal compounds having `d^(1) and d^(9)` electrons whereas the compounds containing `d^(0) and d^(10)` configurations are intensely coloured due to charge transfer transitions.
Which of the following compound is not coloured

`Na_(2)CuCl_(4)`

`Na_(2)CdCl_(4)`

`K_(4)Fe(CN)_(6)`

`K_(3)Fe(CN)_(6)`

Verified by Experts

The correct Answer is:

`Na_(2)CdCl_(4)` contains `Cd^(2+)` which has `4d^(10)` configuration and thus colourless.

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Transition metal compound are coloured due to d-d and charge transfer tranditoins, Colour due to d-d transition is shown by transition metal compounds having d^(1) and d^(9) electrons whereas the compounds containing d^(0) and d^(10) configurations are intensely coloured due to charge transfer transitions. For the same transition metal ion, the colour of its compounds will depend upon

` Na_2CdCl_2`

Pressure of the reaction

Nature of ligands or Lewis bases attached to the metal ion

Concentration of the ligands

Unpaired d-electron

Transfer of an electron

Intermolecular vibrations

Presence of water molecules

`KMnO_4`

`K_2Cr_2 O_7`

`Fe(OH)_3`

`Cr(OH)_2`