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The volume of a colloidal particle VC as...

The volume of a colloidal particle `V_C` as compared to the volume of a solute particle in a true solution `V_S` could be

A

`(V_(c))/(V_(s))~~1`

B

`(V_(c))/(V_(s))~~10^(23)`

C

`(V_(c))/(V_(s))~~10^(-3)`

D

`(V_(c))/(V_(s))~~10^(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
For true solutions, the diameter range of the particles is `1Å` to `10Å` and for colloidal particles, it is `10Å` to `1000Å`
`therefore(V_(c))/(V_(s))=((4//3)pir_(c)^(3))/((4//3)pir_(s)^(3))=((r_(C))/(r_(s)))^(3)=((10)/(1))^(3)=10^(3)`
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Knowledge Check

  • The volume of a colloidal particle, V_C cas compared to the volume of a solute particle in a true solution V_S could be

    A
    `(V_C)/(V_S) ~= 10^3`
    B
    `(V_C)/(V_S)~= 10^(-3)`
    C
    `(V_C)/(V_S) ~= 10^(23)`
    D
    `(V_C)/(V_S) ~= 1`

  • The volume of a colloidal particle, V_(c) as compared to the volume of a solute particle, V_(s) in a true solution could be

    A
    `(V_(s))/(V_(c))~~10^(-3)`
    B
    `(V_(s))/(V_(c))~~10^(3)`
    C
    `(V_(c))/(V_(s))~~1`
    D
    `(V_(c))/(V_(s))~~10^(23)`

  • The volume of colloidal particles V_c as compared ot the volume of solute particles in true solution V_c could be :

    A
    `~1`
    B
    `~10^(23)`
    C
    `~ 10^(-3)`
    D
    `~10^3`

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