The volume of a colloidal particle `V_C` as compared to the volume of a solute particle in a true solution `V_S` could be

Options

A. `(V_(c))/(V_(s))~~1`
B. `(V_(c))/(V_(s))~~10^(23)`
C. `(V_(c))/(V_(s))~~10^(-3)`
D. `(V_(c))/(V_(s))~~10^(3)`

Answer

D

Explanation

For true solutions, the diameter range of the particles is `1Å` to `10Å` and for colloidal particles, it is `10Å` to `1000Å`
`therefore(V_(c))/(V_(s))=((4//3)pir_(c)^(3))/((4//3)pir_(s)^(3))=((r_(C))/(r_(s)))^(3)=((10)/(1))^(3)=10^(3)`