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[Ti(H(2)O)(6)]^(3+) is coloured while [...

`[Ti(H_(2)O)_(6)]^(3+)` is coloured while `[Sc(H_(2)O)_(6)]^(3+)` is colourless. Why?

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In `[Ti(H_(2)O)_(6)]^(3+), Ti^(3+)` ion has one electron in the d-subshell (lower energy `t_(2g)` d-orbitals, has the configuration `t_(2g)^(1)e_(g)^(0)`) which can absorb light in the visible region resulting into d-d transition (jump into higher energy `e_(g)` orbitals). As a result, green and yellow portions of light are absorbed. The complex has the complementary colour, viz, purple. In `[Sc(H_(2)O)_(6)]^(3+)`, `Sc^(3+)` has no d-electron. Hence, no light is absorbed for d-d transition. Hence, it is colourless.
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[Sc(H_(2)O)_(6)]^(3+) ion is

[Sc(H_(2)O)_(6)]^(3+) ion is

(a). Why Mn^(2+) compounds are more stable than Fe^(2+) towards oxidation to their +3 state? (b). Calculate the magnetic moment of V^(3+) ion. (c). [Ti(H_2O)_6_^(3+) gives violet coloured aqueous solution but [Mg(H_2O)_6]^(2+) solution is colourless. (d). [Ti(H_2O)_6]^(3+) is coloured whereas [Sc(H_2O)_6]^(3+) is colourless. Why?

These questions consist of two statements each, printed as Assertion and Reason. While answering these questions you are required to choose any one of the following four responses: Assertion: [Ti(H_2O)_6]^(3+) is coloured while [Sc(H_2O)_6]^(3+) is colourless. Reason: d-d transition is not possible in [Sc(H_2O)_6]^(3+) .

The colour of [Ti(H_(2)O)_(6)]^(3+) is due to

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