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[Cr(NH3)6]^(3+) is paramagnetic while [N...

`[Cr(NH_3)_6]^(3+)` is paramagnetic while `[Ni(CN)_4]^(2-)` is diamagnetic. Explain why?

Text Solution

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`[Cr(NH_(3))_(6)]^(3+)`, `[Ni(CN)_(4)]^(2-)`.
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Why is [NiCl_(4)]^(2-) paramagnetic while [Ni(CN)_(4)]^(2-) is diamagnetic ?

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Knowledge Check

  • Give reason for the statement [Ni(CN)_(4)]^(2-) is diamagnetic while [NiCl_(4)]^(2-) is paramagnetic in nature .

    A
    In `[NiCl_(4)]^(2-)` no unpaired electrons are present while in `[Ni(CN)_(4)]^(2-)` two unpaired electrons are present
    B
    In `[Ni(CN)_(4)]^(2-)` , no unpaired electrons are present while in `[NiCl_(4)]^(2-)` two unpaired electrons are present .
    C
    `[NiCl_(4)]^(2-)` shows `dsp^(2)` hybridisation hence it is paramagnetic .
    D
    `[Ni(CN)_(4)]^(2-)` shows `sp^(3)` hybridisation hence it is diamagnetic .
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    (i) Write the geometrical isomer of the complex [Co(en)_(2)Cl_(2)]^(+) . (ii) [NiCl_(4)]^(2-) is paramagnetic while [Ni(CN)_(4)]^(2-) is diamagnetic through both are tetrahedral . Why ?

    How will you account for the following : (i) [Fe(CN)_6]^(-) is weakly paramagnetic while [Ni(CN)_4]^(2+) diamagnetic. (ii) [Ni(CO)_4] possess tetrahedral geometry while [Ni(CN)_4]^(2-) is square planar.

    [Ni(CN)_(4)]^(2-) is diamagnetic while [Cr(NH_(3))_(6)]^(3+) is paramagnetic. Explain.

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    [Fe(H_2O)_6]^(3+) is strongly paramagnetic whereas [Fe(CN)_6]^(3-) is weakly paramagnetic. Explain.

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