Glucose or sucrose are soluble in water but cyclohexane or bezene (simple six membered ring compounds) are insoluble in water. Explain.

Explanation

Glucose contains five and sucrose contains eight `-OH` groups. These `-OH` groups form H-bonds with water. Due to this extensive intermolecular H-bonding, glucose and sucrose are soluble in water irrespective of the fact that their molecular masses are `180 "g mol"^(-1)` and `342 "g mol"^(-1)` respectively.
In contrast , benzene (molecular mass `= 78 "g mol"^(-1)`) and cyclohexane (molecular mass `=84 "g mol"^(-)`) are simple molecules having low molecular masses. Even than they are insoluble in water. The reason being that these compounds do not contain `-OH` groups and hence do not form H-bonds with water. Alternatively,like dissolves like is the general rule of solubility. THerefore, benzene and cylohexane which are non - polar molecules do not dissolve in polar water molecules while glucose and sucroe being polar molecules dissolve in polar water molecules.