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0.1 mol of a carbonhydrate with empirica...

`0.1 mol` of a carbonhydrate with empirical formula `CH_(2)O` contains `1 g` of hydrogen. What is its molecular formula?

A

`C_(5)H_(10)O_(5)`

B

`C_(6)H_(12)O_(6)`

C

`C_(4)H_(8)O_(4)`

D

`C_(3)H_(6)O_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
0.1 mole of carbohydrate with E.F. `CH_(2)O` contains 1 g of hydrogen.
`therefore "1 mole of carbohydrate will contain hydrogen"`
= 10 g = 10 g atoms
In `CH_(2)O`, g atomic ratio of `C:H:O=1:2:1`
`therefore" With 10 g atom of H, g atoms of C combined"`
`="5 and g atoms of O combined = 5. Hence, actual formula (molecular formula) will be "C_(5)H_(10)O_(5)`.
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Carbohydrates are compounds containing only carbon, hydrogen and oxygen having the atomic ratio of H : O as 2 : 1 . When heated in the absence of air, these compounds decompose to form carbon and water. a. If 310 g of a carbohydrates leaves a residue of 124 g of carbon on heating in absence of air, whatis the empirical formula of the carbohydrate? If 0.0833 mole of hte carbohydrate contains 1.0 g hydrogen , what is the molecular formula of the carbohydrate?

Knowledge Check

  • 0.0833 mol of carbohydrate of empirical formula CH_(2)O contain 1g of hydrogen . The molecular formula of the carbonydrate is

    A
    `C_(5)H_(10)O_(5)`
    B
    `C_(3)H_(4)O_(3)`
    C
    `C_(12)H_(22)O_(11)`
    D
    `C_(6)H_(12)O_(6)`

  • 0.0833 mol of carbohydrate of empirical formula CH_(2)O contain 1 g of hydrogen. The molecular formula of the carbohydrate is

    A
    `C_(5)H_(10)O_(5)`
    B
    `C_(3)H_(4)O_(3)`
    C
    `C_(12)H_(22)O_(11)`
    D
    `C_(6)H_(12)O_(6)`

  • 0.833 mole of a carbohydrate, with empirical formula CH_2 O has 10 g of hydrogen. Molecular formula of carbohydrate is

    A
    `C_6 H_(12) O_6`
    B
    `C_3 H_5 O_3`
    C
    `C_3 H_(10) O_5`
    D
    `C_3 H_4 O_3`

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