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What is the mass of the precipitate form...

What is the mass of the precipitate formed when 50 mL of 16.9% solution of `AgNO_(3)` is mixed with 50 mL of 5.8% NaCl solution?

A

7 g

B

14 g

C

28 g

D

3.5 g

Text Solution

Verified by Experts

The correct Answer is:
A
50 mL of `16.9%AgNO_(3)` solution contaion `AgNO_(3)`
`=(16.9)/(100)xx50=8.45g`
50 mL of `5.8%` NaCl solution contains NaCl
`=(5.8)/(100)xx50=2.9g`
`{:(" "AgNO_(3),+,NaCl,rarr,AgCl + NaNO_(3)),(107.8+14+48,+,23+35.5,,108+35.5),(=169.8g,,=58.5g,,=143.5g):}`
`8.45" g of "AgNO_(3)` reacts with `NaCl=(58.5)/(169.8)xx8.45g`
`=2.9g`
Thus, the amounts present react completely
`therefore" AgCl formed"=(143.5)/(169.8)xx8.45g~=7g`
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Knowledge Check

  • What is the mass of the precipitate formed when 50 mL of 16.9% solution of AgNO, is mixed with 50 mL of 5.8% NaCl solution? (Ag = 107.8, N = 14,0 = 16, Na - 23, C1= 35.5)

    A
    3.5 g
    B
    7 g
    C
    14 g
    D
    28 g

  • What is the mass of precipitate formed when 50mL of 16.9% solution of AgNO_3 is mixed with 50 mL of 5.8% NaCI solution? 9Ag=107.8,N=14,O=16,Na=23CI=35.5)

    A
    28g
    B
    3.5 g
    C
    7 g
    D
    14 g

  • What is the mass of the precipitate formed when 50 mL of 16.9 % (w//v ) solution of Ag NO_(3) is mixed with 50 mL of 5.8 % (w/v) NaCl solutions (Ag = 107.3 ,N=14,O=16 ,Na=23 ,Cl=35.5)

    A
    7g
    B
    14g
    C
    28g
    D
    `3.5g`

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