What is the mass of the precipitate formed when 50 mL of 16.9% solution of `AgNO_(3)` is mixed with 50 mL of 5.8% NaCl solution?

Options

A. 7 g
B. 14 g
C. 28 g
D. 3.5 g

Answer

A

Explanation

50 mL of `16.9%AgNO_(3)` solution contaion `AgNO_(3)`
`=(16.9)/(100)xx50=8.45g`
50 mL of `5.8%` NaCl solution contains NaCl
`=(5.8)/(100)xx50=2.9g`
`{:(" "AgNO_(3),+,NaCl,rarr,AgCl + NaNO_(3)),(107.8+14+48,+,23+35.5,,108+35.5),(=169.8g,,=58.5g,,=143.5g):}`
`8.45" g of "AgNO_(3)` reacts with `NaCl=(58.5)/(169.8)xx8.45g`
`=2.9g`
Thus, the amounts present react completely
`therefore" AgCl formed"=(143.5)/(169.8)xx8.45g~=7g`