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Propene is the treadted wit BrC CI(3) ...

Propene is the treadted wit `BrC CI_(3)` is presence of peroxides.

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In presence of peroxides `Br C CI_(3)` undergoes homolytic fission to form `C CI_(3)` radical which then attacks the propene molecule at the `CH_(2)` group to form a `2^(@)` alkyl free radical . This radical subsequently reacts with `BrCCI_(3)` to complete the addition.

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What happens when : (i) Propene is treated with HBr in presence of peroxide. (ii) Benzene is treated with methyl chloride in presence of AlCl_(3)

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Knowledge Check

  • When propene is reacted with HBr in the presence of peroxide. The species first attack on propene is

    A
    `Br^(+)`
    B
    `Br^(-)`
    C
    `H^(*)`
    D
    `Br^(*)`
  • Propene is allowed to react with HBr in the presence of benzoyl peroxide and the product is subsequently heated with aqueous KOH . The final product obtained is

    A
    propane -`1-ol`
    B
    propane-`2-ol`
    C
    propane-`1,2`-diol
    D
    propane-`1,3`-diol
  • When prepane is treated with HCl in the presence of peroxide gives

    A
    `CH_(3) CH_(2) CH_(2) l`
    B
    `CH_(3)CHClCH_(3)`
    C
    `(CH_(3))_(2)CCl`
    D
    `CH_(3)CH_(2)Cl`
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    When 3-phenyl propene is treated with HBr in the presence of proxide, the major product formed is

    1-butane reacts with HBr in presence of peroxide given

    Assertion : Propene reacts with HBr in the presence of peroxides to give 1-bromopropane. Reason : Alkenes react with HBr in the presence of peroxides according to anti Markovnikov's rule.

    What would be the main product when propene reacts with HBr is presence of benzoyl peroxide ?

    Assertion : Propene reacts with HBr in presence of benzoyl peroxide to yield 1- bromopropane. Reason : In presence of peroxide , the addition of HBr to propane follows ionic mechanism.