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In Figure, A B C D is a cyclic quadrilat...

In Figure, `A B C D` is a cyclic quadrilateral. Find the value of `x`

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We have, `/_CDA =180^0-100^0=100^0`
`/_ABC=180^0-x`
Now,`/_CDA+/_ABC=180^0`
`=>100^0+180^0-x=180^0`
`x=100^0`
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