A compound contains `4.2%` hydrogen, `24.2%` carbon and `71.6%` chlorine by mass. Its molar mass is `98.96 gm//mol`. Empirical formula of compound is :
A
`CH_(2)CI`
B
`C_(2)H_(4)CI_(2)`
C
`C_(2)H_(2)CI_(2)`
D
`C_(4)H_(4)CI_(4)`
Text Solution
Verified by Experts
The correct Answer is:
A
A compound contains ………………. `|(,"Mass(gm)","Mole",,underset("strength")underset("Molar")("Relative"),underset("formula")("Empirical")),(C,24.2,underset(=2.01)((24.2)/12),,1,),(H,4.2,underset(=4.2)(4.2/1),,2,C_(1)H_(2)Cl),(Cl,71.6,underset(=2.01)(71.6/35.5),,1,)|`
Topper's Solved these Questions
TEST PAPERS
RESONANCE|Exercise PART - III CHEMISTRY SEC - 1|12 Videos
TEST PAPERS
RESONANCE|Exercise PART - III CHEMISTRY SEC - 2|18 Videos
SURFACE CHEMISTRY
RESONANCE|Exercise Section - 5|1 Videos
TEST SERIES
RESONANCE|Exercise CHEMISTRY|50 Videos
Similar Questions
Explore conceptually related problems
A compound contains 4.07% hydrogen, 24.27% carbon and 71.65% chlorine. Its molar mass is 98.96 g. What are its empirical and molecular formulas?
A compound contains 4.07 % hydrogen, 24.27% carbon and 71.65% chlorine. Its molecular mass is 98.96. What are its empirical and molecular formulae ?
A compound contains 4.07% H, 24.27% C , and 71.65% Cl . If its molar mass is 98.96 , the molecular formula will be
A compound contains C=90% and H=10% Empirical formula of the compound is:
A compound contains 34.8% Oxygen, 52.2% carbon and 13.0% Hydrogen. What is the empirical formula of the compound ?
An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C,38.71% and H,9.67% . The empirical formula of the compound would be :