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A force F is applied on a block of mass ...

A force `F` is applied on a block of mass `5 kg` as shown in figure. Co-efficient of friction between the wall and clock is `(sqrt(3))/(2). (g = 10m//s^(2))`

Select correct option(s)

A

Magnitude of minimum force `F` so that block doesn't slip on the wall is `40 N`.

B

Magnitude of minimum force `F` so that block doesn't slip on the wall is `20 N`.

C

If `F lt 40N` then block will side downwards

D

If `F lt 40N` then block will slide upwards

Text Solution

Verified by Experts

The correct Answer is:
A, C
`(F)/(2) + mu(Fsqrt(3)/(2)) = 50`
`rArr (F)/(2) + F xx (3)/(4) = 50 rArr (5F)/(4) = 50 rArr F = 40N`
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Knowledge Check

  • A force F" is applied on a block of mass 5 kg as shown in figure. Co-efficient of friction between the wall and clock is (sqrt(3))/(2). (g = 10m//s^(2)) If 'f_(1)" and 'f_(2)' are magnitude of frictional force on the block when F = 40 N and F = 140 N repesctively. Then choose correct options

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