The range for a projectile that lands at the same elevation from which it is fired is given by `R = (u^(2)//g) sin 2theta`. Assume that the angle of projection `= 30^(@)`. If the initial speed of projection is increased by `1%`, while the angle of projection is decreased by `2%` then the range changes by

Options

A. `-0.3%`
B. `+ 4.3%`
C. `+ 0.65%`
D. `0.85%`

Answer

D

Explanation

`deltaR//R = 2 deltau//u + 2 cot2theta " "delta theta`