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The range for a projectile that lands at...

The range for a projectile that lands at the same elevation from which it is fired is given by `R = (u^(2)//g) sin 2theta`. Assume that the angle of projection `= 30^(@)`. If the initial speed of projection is increased by `1%`, while the angle of projection is decreased by `2%` then the range changes by

A

`-0.3%`

B

`+ 4.3%`

C

`+ 0.65%`

D

`0.85%`

Text Solution

Verified by Experts

The correct Answer is:
D
`deltaR//R = 2 deltau//u + 2 cot2theta " "delta theta`
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The range for a projectile that lands at the same elevation from which it is fired is given by R=(u^2//g) sin 2theta . Assume that the angle of projection = 30^@ . If the initial speed of projection is increased by 1% , while the angle of projection is decreased by 2% . Then by what percentage does the range change ?

The maximum range of projectile is 2/ √ 3 times actual range. What isthe angle of projection for the actual range ?

Knowledge Check

  • The range of a projectile is R when the angle of projection is 40^(@) . For the same velocity of projection and range, the other possible angle of projection is

    A
    `45^(@)`
    B
    `50^(@)`
    C
    `60^(@)`
    D
    `40^(@)`

  • Range of a projectile is R, when the angle of projection is 30^(@) . Then, the value of the other angle of projection for the same range is

    A
    `45^(@)`
    B
    `60^(@)`
    C
    `50^(@)`
    D
    `40^(@)`

  • Keeping the speed of projection constant, the angle of projection is increased from 0^(@) to 90^(@) . Then the horizontal range of the projectile

    A
    goes on increasing up to `90^(@)`
    B
    decreases up to `90^(@)`
    C
    increases up to `45^(@)` and decreases afterwards
    D
    decreases up to `45^(@)` and increases afterwards

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