Home
Class 12
PHYSICS
The potential energy function for the fo...

The potential energy function for the force between two in a diatomic molecule can approximately be expressed as `U(x)=(a)/(x^(12))-(b)/(x^(4))`, where `a` and `b` are positive constants, and `x` is the distance between the atoms. Answer the following question by selecting most appropriate alternative.
The graph between potential energy vs `x` will be

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
B

`U(x)=(a)/(x^(12))-(b)/(x^(6))`
`(delta u)/(delta x)=-(12a)/(x^(13))+(6b)/(x^(7))`
For `(delta u)/(delta x)=0 rArr (2a)/(b)=x^(6)`
For `x rArr 0 " " U rarr + oo`
For `x rarr oo " " U rarr 0` from negative side
`U=0 rArr x = root(6)(a/b)`
Hence (B) is correct.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • WORK, ENERGY AND POWER

    FIITJEE|Exercise ASSIGNMENT PROBLEMS ( OBJECTIVE) (LEVEL-II)|19 Videos
  • TEST PAPERS

    FIITJEE|Exercise PHYSICS|747 Videos

Similar Questions

Explore conceptually related problems

The potential energy function for the force between two in a diatomic molecule can approximately be expressed as U(x)=(a)/(x^(12))-(b)/(x^(4)) , where a and b are positive constants, and x is the distance between the atoms. Answer the following question by selecting most appropriate alternative. The graph between force between the atoms [F(x)] vs x will be

The potential energy function for the force between two in a diatomic molecule can approximately be expressed as U(x)=(a)/(x^(12))-(b)/(x^(4)) , where a and b are positive constants, and x is the distance between the atoms. Answer the following question by selecting most appropriate alternative. The dissociation energy of the molecule is (initially molecule is at rest at equilibrium)

Knowledge Check

  • The potential energy between two atoms in a molecule is given by U(x)= (1)/(x^(12))-(b)^(x^(6)) , where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibirum when

    A
    `x = 6sqrt((11a)/(5b))`
    B
    `x = 6sqrt((a)/(2b))`
    C
    `x =0`
    D
    `x = 6sqrt((2a)/(b))`
  • The potential energy funtions for the force between two along in a distance molecule is approximatily given by U(x) = (a)/(x^(12)) - b)/(x^(6)) where a and b are constant and x is the distance between the aloms , if the discision energy of the molecale is D = [U(x = oo) - U atequlibrium ] , D is

    A
    `(b^(2))/(2a)`
    B
    `(b^(2))/(12a)`
    C
    `(b^(2))/(4a)`
    D
    `(b^(2))/(6a)`
  • The potential energy between two atoms in a molecule is given by U=ax^(2)-bx^(2) where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibrium when x is equal to :-

    A
    `0`
    B
    `(2b)/(3a)`
    C
    `(3a)/(2b)`
    D
    `(3b)/(2a)`
  • Similar Questions

    Explore conceptually related problems

    The potential energy function for the force between two atoms in a diatomic molecule is approximately given by U(x) =a/x^(12)-b/x^(6) where a and b are constant and x is the distance between the atoms. Find the dissoociation energy of the molecule which is given as D=[U(x- infty)-U_(at equilibrium)]

    The potential energy function for the force between two atoms in a diatomic molecule is approximate given by U(r) = (a)/(r^(12)) - (b)/(r^(6)) , where a and b are constants and r is the distance between the atoms. If the dissociation energy of the molecule is D = [U (r = oo)- U_("at equilibrium")],D is

    The potential energy between two atoms in a molecule is given by, U_((x))=(a)/x^(12)-(b)/x^(6) , where a and b are positive constant and x is the distance between the atoms. The atoms is an stable equilibrium, when-

    If potential energy function for the force between two atoms in a diatomic molecule is approximately given by U(x)=(a)/(x^(8))-(b)/(x^(4)) , where a and b are constants in standard SI units and x in meters. Find the dissociation energy of the molecule (in J). ["Take a "="4 J m"^(8) and b="20 J m"^(4)]

    In a molecule, the potential energy between two atoms is given by U (x) = (1)/(x^(12)) -(b)/(x^(6)) . Where 'a' and 'b' are positive constants and 'x' is the distance between atoms. Find the value of 'x' at which force is zero and minimim P.E at that point.