Home
Class 12
PHYSICS
A uniform chain of length l is placed on...

A uniform chain of length `l` is placed on rough table with length `l//n` (where `n gt 1`) , hanging over the edge. If the chain just begins to slide off the table by itself from this position, the coefficient of friction between the chain and the table is

A

`1//n`

B

`1//(n-1)`

C

`1//(n+1)`

D

`(n-1)//(n+1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEM

    RESONANCE|Exercise DPP No.20|9 Videos

  • DAILY PRACTICE PROBLEM

    RESONANCE|Exercise DPP No.21|20 Videos

  • DAILY PRACTICE PROBLEM

    RESONANCE|Exercise DPP No.18|9 Videos

  • CURRENT ELECTRICITY

    RESONANCE|Exercise High Level Problems (HIP)|21 Videos

  • ELECTRO MAGNETIC WAVES

    RESONANCE|Exercise Exercise 3|27 Videos

Similar Questions

Explore conceptually related problems

A uniform chain of length l is placed on a rough table, with length l//3 hanging over the edge. If the chain just begins to slide off the table by itself from this portion, the coefficient of friction between the chain and the table is 1/K. Then find the value of K.

25% of a uniform chain hangs from the edge of a horizontal table top. If the chain is on the verge of sliding,the coefficient of static friction between the chain and horizontal table is

Knowledge Check

  • A unifrom heavy chain is placed on a table with a part of it hanging over the edge. It just begins to slide when this part is one-third of its length. The coefficient of friction between the table and the chain is

    A
    `(1)/(2)`
    B
    `(1)/(3)`
    C
    `(2)/(3)`
    D
    `(3)/(4)`

  • A chain is lying on a rough table with a fraction 1/n of its length hanging down from the edge of the table. if it is just on the point of sliding down from the table, then the coefficient of friction between the table and the chain is -

    A
    `(1)/(n)`
    B
    `(1)/((n-1))`
    C
    `(1)/((n+1))`
    D
    `(n-1)/((n+1))`

  • A uniform chain has a mass M and length L. It is placed on a frictionless table with length l_(0) hanging over the edge. The chain begins to slide down. Ten, the speed v with which the end slides down from the edge is given by

    A
    `v=sqrt((g)/(L)(L+l_(0)))`
    B
    `v=sqrt((g)/(L)(L-l_(0)))`
    C
    `v=sqrt((g)/(L)(L^(2)-l_(0)^(2)))`
    D
    `v=sqrt(2g`(L-l_(0)))`

    • Similar Questions

    Explore conceptually related problems

    A uniform chain of mass m and length l is lying on a horizontal table with one-third of its length hanging over the edge of the table. If the chain is limiting equlibrium, what is the coefficient of friction for the contact between table and chain?

    A uniform chain of mass m and length l is lying on a horizontal table with one-third of its length hanging over the edge of the table. What is the speed of the chain, when it just loses contact with the table?

    A uniform chain of length l and mass m is placed on a smooth table with one-fourth of its length hanging over the edge. The work that has to be done to pull the whole chain back onto the table is :

    A uniform chain of length L is resting on a table with a part of its hanging over the edge . If the coefficient of static friction between the chain and the table is mu , the maximum length of the hanging part is

    A chain of mass m and length l is placed on a table with one-sixth of it hanging freely from the table edge. The amount of work. done to pull the chain on the table is

    Home
    Profile