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A galvanometer having 30 divisions has a...

A galvanometer having `30` divisions has a current sensitivity of `20muA//di vision`. It has a resistance of `25Omega`. How will you convert it into an ammeter upto 1 ampere? How will you convert this ammeter into a voltmeter up to 1 volt?

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The correct Answer is:
`S=(15xx10^(3))/(1-0.6xx10^(3))=0.0015Omega" in parallel R"=0.985 Omega" series"`.
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A galvanometer having 30 divisions has a current sensitivity of 20 muA//"division" . It has a resistance of 20Omega . How will you convert it into an ammeter measuring upto 1 ampere? How will you convert this ammeter into voltmeter reading upto 1 volt?

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