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A galvanometer having 30 divisions has a...

A galvanometer having `30` divisions has a current sensitivity of `20muA//di vision`. It has a resistance of `25Omega`. How will you convert it into an ammeter upto 1 ampere? How will you convert this ammeter into a voltmeter up to 1 volt?

Text Solution

Verified by Experts

The correct Answer is:
`S=(15xx10^(3))/(1-0.6xx10^(3))=0.0015Omega" in parallel R"=0.985 Omega" series"`.
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Knowledge Check

  • A galvanometer has a resistance of 30Omega and a current of 2*0mA gives full scale deflection. How will you convert this galvanometer into a voltmeter of 0*2 volt range?

    A
    `700Omega` resistance should be connected parallel to the galvanometer
    B
    `70Omega` resistance should be connected parallel to the galvanometer
    C
    `700Omega` resistance should be connected in series with the galvanometer
    D
    `70Omega` resistance should be used in series with the galvanometer

  • A galvanometer of resistance 20 Omega has current senstivity of 5 div/mA. The instrument has 50 divisions. How will you convert it into voltmeter reading upto 25 volt?

    A
    join a resistance of 1240 Omega in series
    B
    join a resistance of 2480 Omega in series
    C
    join a resistance of 2480 Omega in parallel
    D
    join a shunt of 20 Omega

  • A galvanometer has resistance of 7Omega and given a full scale deflection for a current of 1.0A . How will you convert it into a voltmeter of range 10V

    A
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