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When force vec(F)(1),vec(F)(2),vec(F)(3)...

When force `vec(F)_(1),vec(F)_(2),vec(F)_(3)` are acting on a particle of mass `m`, the particle remains in equilibrium. If the force `vec(F)_(1)` is now removed then the acceleration of the particle is :

A

`vec(F)_(1)//m`

B

`vec(F)_(1)//m`

C

`vec(F)_(2)-vec(F)_(3)//m`

D

`vec(F)_(2)//m`

Text Solution

Verified by Experts

The correct Answer is:
B
As initially `vec(F)_(1)+vec(F)_(2)+vec(F)_(3)=0`
If `vec(F)_(1)` is deleted
then `vecF_("net") = vec(F)_(2) +vec(F)_(3)=ma vec(a)=(vec(F)_(2)+vec(F)_(3))/(m)=(vec(F_(1)))/(m)`
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RESONANCE-DAILY PRACTICE PROBLEM-DPP No.23
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