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If the mth term of an A.P. be 1//n and n...

If the mth term of an A.P. be `1//n` and nth term be `1//m` then show that its (`m n` )th term is 1.

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To solve the problem, we need to show that if the m-th term of an A.P. (Arithmetic Progression) is \( \frac{1}{n} \) and the n-th term is \( \frac{1}{m} \), then the \( mn \)-th term is equal to 1. ### Step-by-Step Solution: 1. **Define the terms of the A.P.:** Let the first term of the A.P. be \( a_1 \) and the common difference be \( d \). 2. **Write the expressions for the m-th and n-th terms:** ...
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Knowledge Check

  • If the mth term of an A.P. is (1/n) and the nth term is (1/m), then its (mn)^(th) term is:

    A
    `-mn`
    B
    `-1`
    C
    1
    D
    `1//mn`

  • If mth term of an AP is 1/n and nth term is 1/m then mnth term of the AP is

    A
    `(1)/(mn)`
    B
    mn
    C
    1
    D
    none of these

  • If the mth term of an AP is 1/n and nth term is 1/m, then find the sum to mn terms.

    A
    ( mn – 1)/4
    B
    (mn + 1)/4
    C
    (mn + 1)/2
    D
    (mn - 1)/2

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