Find the 9th term in the expansion of `(x/a-(3a)/(x^2))^(12)` .

Explanation

To find the 9th term in the expansion of \((\frac{x}{a} - \frac{3a}{x^2})^{12}\), we can use the Binomial Theorem. The general term in the expansion of \((a + b)^n\) is given by:

\[ T_{r+1} = \binom{n}{r} a^{n-r} b^r \]

In our case, we have \(n = 12\), \(a = \frac{x}{a}\), and \(b = -\frac{3a}{x^2}\).

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