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If (b+c)/a ,(c+a)/b ,(a+b)/c are in A.P....

If `(b+c)/a ,(c+a)/b ,(a+b)/c` are in A.P., prove that : `b c ,\ c a ,\ a b` are in A.P.

Text Solution

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Since, `1/a, 1/b , 1/c` are in A.P.
`1/b-1/a=1/c=1/b` are in A.P we have,
`=>(a-b)/ab=(b-c)/bc`
`=> (a-b)/a=(b-c)/c`
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