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The electric field associated with a mon...

The electric field associated with a monochromataic beam of light becomes zero, `2.4xx10^(15)` times per second. Find the maximum kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0eV, `h=6.63xx10^(-34)Js`.

Text Solution

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The correct Answer is:
`(0.6xx10^(15)h-2e)J=0.48eV`
frequency of the light
`=(1)/(2)xx1.2xx10^(15)=0.6xx10^(15)Hz`
`KE=hv - phi=0.48 eV`
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Knowledge Check

  • The work function of a metal is 2.5eV . The maximum kinetic energy of the photoelectrons emitted if a radiof wavelength 3000A^(0) falls on it is (h=6.63xx10^(-34)Js & c=3xx10^(8)m//s)

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  • The kinetic energy of the electron emitted when light of frequency 3.5 xx 10^15 H z falls on a metal surface having threshold frequency 1.5 xx 10^15 H z is (h = 6.6 xx 10^-34 Js) .

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    `1.32 xx 10^-18 J`
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    `3.3 xx 10^-18 J`
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    `6.6 xx 10^-19 J`
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